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authorRoman Divacky <rdivacky@FreeBSD.org>2010-01-01 10:31:22 +0000
committerRoman Divacky <rdivacky@FreeBSD.org>2010-01-01 10:31:22 +0000
commit1e7804dbd25b8dbf534c850355d70ad215206f4b (patch)
treedba00119388b84f9f44e6ec5e9129f807fd79ca3 /lib/Support/StringRef.cpp
parent571945e6affd20b19264ec22495da418d0fbdbb4 (diff)
Notes
Diffstat (limited to 'lib/Support/StringRef.cpp')
-rw-r--r--lib/Support/StringRef.cpp40
1 files changed, 40 insertions, 0 deletions
diff --git a/lib/Support/StringRef.cpp b/lib/Support/StringRef.cpp
index 2d023e4895d06..e4a9984828f3e 100644
--- a/lib/Support/StringRef.cpp
+++ b/lib/Support/StringRef.cpp
@@ -8,6 +8,7 @@
//===----------------------------------------------------------------------===//
#include "llvm/ADT/StringRef.h"
+#include "llvm/ADT/SmallVector.h"
using namespace llvm;
// MSVC emits references to this into the translation units which reference it.
@@ -35,6 +36,45 @@ int StringRef::compare_lower(StringRef RHS) const {
return Length < RHS.Length ? -1 : 1;
}
+// Compute the edit distance between the two given strings.
+unsigned StringRef::edit_distance(llvm::StringRef Other,
+ bool AllowReplacements) {
+ // The algorithm implemented below is the "classic"
+ // dynamic-programming algorithm for computing the Levenshtein
+ // distance, which is described here:
+ //
+ // http://en.wikipedia.org/wiki/Levenshtein_distance
+ //
+ // Although the algorithm is typically described using an m x n
+ // array, only two rows are used at a time, so this implemenation
+ // just keeps two separate vectors for those two rows.
+ size_type m = size();
+ size_type n = Other.size();
+
+ SmallVector<unsigned, 32> previous(n+1, 0);
+ for (SmallVector<unsigned, 32>::size_type i = 0; i <= n; ++i)
+ previous[i] = i;
+
+ SmallVector<unsigned, 32> current(n+1, 0);
+ for (size_type y = 1; y <= m; ++y) {
+ current.assign(n+1, 0);
+ current[0] = y;
+ for (size_type x = 1; x <= n; ++x) {
+ if (AllowReplacements) {
+ current[x] = min(previous[x-1] + ((*this)[y-1] == Other[x-1]? 0u:1u),
+ min(current[x-1], previous[x])+1);
+ }
+ else {
+ if ((*this)[y-1] == Other[x-1]) current[x] = previous[x-1];
+ else current[x] = min(current[x-1], previous[x]) + 1;
+ }
+ }
+ current.swap(previous);
+ }
+
+ return previous[n];
+}
+
//===----------------------------------------------------------------------===//
// String Searching
//===----------------------------------------------------------------------===//