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Diffstat (limited to 'contrib/llvm/lib/CodeGen/MachineOutliner.cpp')
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diff --git a/contrib/llvm/lib/CodeGen/MachineOutliner.cpp b/contrib/llvm/lib/CodeGen/MachineOutliner.cpp new file mode 100644 index 000000000000..581a8ad81149 --- /dev/null +++ b/contrib/llvm/lib/CodeGen/MachineOutliner.cpp @@ -0,0 +1,1251 @@ +//===---- MachineOutliner.cpp - Outline instructions -----------*- C++ -*-===// +// +//                     The LLVM Compiler Infrastructure +// +// This file is distributed under the University of Illinois Open Source +// License. See LICENSE.TXT for details. +// +//===----------------------------------------------------------------------===// +/// +/// \file +/// Replaces repeated sequences of instructions with function calls. +/// +/// This works by placing every instruction from every basic block in a +/// suffix tree, and repeatedly querying that tree for repeated sequences of +/// instructions. If a sequence of instructions appears often, then it ought +/// to be beneficial to pull out into a function. +/// +/// This was originally presented at the 2016 LLVM Developers' Meeting in the +/// talk "Reducing Code Size Using Outlining". For a high-level overview of +/// how this pass works, the talk is available on YouTube at +/// +/// https://www.youtube.com/watch?v=yorld-WSOeU +/// +/// The slides for the talk are available at +/// +/// http://www.llvm.org/devmtg/2016-11/Slides/Paquette-Outliner.pdf +/// +/// The talk provides an overview of how the outliner finds candidates and +/// ultimately outlines them. It describes how the main data structure for this +/// pass, the suffix tree, is queried and purged for candidates. It also gives +/// a simplified suffix tree construction algorithm for suffix trees based off +/// of the algorithm actually used here, Ukkonen's algorithm. +/// +/// For the original RFC for this pass, please see +/// +/// http://lists.llvm.org/pipermail/llvm-dev/2016-August/104170.html +/// +/// For more information on the suffix tree data structure, please see +/// https://www.cs.helsinki.fi/u/ukkonen/SuffixT1withFigs.pdf +/// +//===----------------------------------------------------------------------===// +#include "llvm/ADT/DenseMap.h" +#include "llvm/ADT/Statistic.h" +#include "llvm/ADT/Twine.h" +#include "llvm/CodeGen/MachineFrameInfo.h" +#include "llvm/CodeGen/MachineFunction.h" +#include "llvm/CodeGen/MachineInstrBuilder.h" +#include "llvm/CodeGen/MachineModuleInfo.h" +#include "llvm/CodeGen/Passes.h" +#include "llvm/IR/IRBuilder.h" +#include "llvm/Support/Allocator.h" +#include "llvm/Support/Debug.h" +#include "llvm/Support/raw_ostream.h" +#include "llvm/Target/TargetInstrInfo.h" +#include "llvm/Target/TargetMachine.h" +#include "llvm/Target/TargetRegisterInfo.h" +#include "llvm/Target/TargetSubtargetInfo.h" +#include <functional> +#include <map> +#include <sstream> +#include <tuple> +#include <vector> + +#define DEBUG_TYPE "machine-outliner" + +using namespace llvm; + +STATISTIC(NumOutlined, "Number of candidates outlined"); +STATISTIC(FunctionsCreated, "Number of functions created"); + +namespace { + +/// \brief An individual sequence of instructions to be replaced with a call to +/// an outlined function. +struct Candidate { + +  /// Set to false if the candidate overlapped with another candidate. +  bool InCandidateList = true; + +  /// The start index of this \p Candidate. +  size_t StartIdx; + +  /// The number of instructions in this \p Candidate. +  size_t Len; + +  /// The index of this \p Candidate's \p OutlinedFunction in the list of +  /// \p OutlinedFunctions. +  size_t FunctionIdx; + +  /// \brief The number of instructions that would be saved by outlining every +  /// candidate of this type. +  /// +  /// This is a fixed value which is not updated during the candidate pruning +  /// process. It is only used for deciding which candidate to keep if two +  /// candidates overlap. The true benefit is stored in the OutlinedFunction +  /// for some given candidate. +  unsigned Benefit = 0; + +  Candidate(size_t StartIdx, size_t Len, size_t FunctionIdx) +      : StartIdx(StartIdx), Len(Len), FunctionIdx(FunctionIdx) {} + +  Candidate() {} + +  /// \brief Used to ensure that \p Candidates are outlined in an order that +  /// preserves the start and end indices of other \p Candidates. +  bool operator<(const Candidate &RHS) const { return StartIdx > RHS.StartIdx; } +}; + +/// \brief The information necessary to create an outlined function for some +/// class of candidate. +struct OutlinedFunction { + +  /// The actual outlined function created. +  /// This is initialized after we go through and create the actual function. +  MachineFunction *MF = nullptr; + +  /// A number assigned to this function which appears at the end of its name. +  size_t Name; + +  /// The number of candidates for this OutlinedFunction. +  size_t OccurrenceCount = 0; + +  /// \brief The sequence of integers corresponding to the instructions in this +  /// function. +  std::vector<unsigned> Sequence; + +  /// The number of instructions this function would save. +  unsigned Benefit = 0; + +  /// \brief Set to true if candidates for this outlined function should be +  /// replaced with tail calls to this OutlinedFunction. +  bool IsTailCall = false; + +  OutlinedFunction(size_t Name, size_t OccurrenceCount, +                   const std::vector<unsigned> &Sequence, +                   unsigned Benefit, bool IsTailCall) +      : Name(Name), OccurrenceCount(OccurrenceCount), Sequence(Sequence), +        Benefit(Benefit), IsTailCall(IsTailCall) +        {} +}; + +/// Represents an undefined index in the suffix tree. +const size_t EmptyIdx = -1; + +/// A node in a suffix tree which represents a substring or suffix. +/// +/// Each node has either no children or at least two children, with the root +/// being a exception in the empty tree. +/// +/// Children are represented as a map between unsigned integers and nodes. If +/// a node N has a child M on unsigned integer k, then the mapping represented +/// by N is a proper prefix of the mapping represented by M. Note that this, +/// although similar to a trie is somewhat different: each node stores a full +/// substring of the full mapping rather than a single character state. +/// +/// Each internal node contains a pointer to the internal node representing +/// the same string, but with the first character chopped off. This is stored +/// in \p Link. Each leaf node stores the start index of its respective +/// suffix in \p SuffixIdx. +struct SuffixTreeNode { + +  /// The children of this node. +  /// +  /// A child existing on an unsigned integer implies that from the mapping +  /// represented by the current node, there is a way to reach another +  /// mapping by tacking that character on the end of the current string. +  DenseMap<unsigned, SuffixTreeNode *> Children; + +  /// A flag set to false if the node has been pruned from the tree. +  bool IsInTree = true; + +  /// The start index of this node's substring in the main string. +  size_t StartIdx = EmptyIdx; + +  /// The end index of this node's substring in the main string. +  /// +  /// Every leaf node must have its \p EndIdx incremented at the end of every +  /// step in the construction algorithm. To avoid having to update O(N) +  /// nodes individually at the end of every step, the end index is stored +  /// as a pointer. +  size_t *EndIdx = nullptr; + +  /// For leaves, the start index of the suffix represented by this node. +  /// +  /// For all other nodes, this is ignored. +  size_t SuffixIdx = EmptyIdx; + +  /// \brief For internal nodes, a pointer to the internal node representing +  /// the same sequence with the first character chopped off. +  /// +  /// This has two major purposes in the suffix tree. The first is as a +  /// shortcut in Ukkonen's construction algorithm. One of the things that +  /// Ukkonen's algorithm does to achieve linear-time construction is +  /// keep track of which node the next insert should be at. This makes each +  /// insert O(1), and there are a total of O(N) inserts. The suffix link +  /// helps with inserting children of internal nodes. +  /// +  /// Say we add a child to an internal node with associated mapping S. The  +  /// next insertion must be at the node representing S - its first character. +  /// This is given by the way that we iteratively build the tree in Ukkonen's +  /// algorithm. The main idea is to look at the suffixes of each prefix in the +  /// string, starting with the longest suffix of the prefix, and ending with +  /// the shortest. Therefore, if we keep pointers between such nodes, we can +  /// move to the next insertion point in O(1) time. If we don't, then we'd +  /// have to query from the root, which takes O(N) time. This would make the +  /// construction algorithm O(N^2) rather than O(N). +  /// +  /// The suffix link is also used during the tree pruning process to let us +  /// quickly throw out a bunch of potential overlaps. Say we have a sequence +  /// S we want to outline. Then each of its suffixes contribute to at least +  /// one overlapping case. Therefore, we can follow the suffix links +  /// starting at the node associated with S to the root and "delete" those +  /// nodes, save for the root. For each candidate, this removes +  /// O(|candidate|) overlaps from the search space. We don't actually +  /// completely invalidate these nodes though; doing that is far too +  /// aggressive. Consider the following pathological string: +  /// +  /// 1 2 3 1 2 3 2 3 2 3 2 3 2 3 2 3 2 3 +  /// +  /// If we, for the sake of example, outlined 1 2 3, then we would throw +  /// out all instances of 2 3. This isn't desirable. To get around this, +  /// when we visit a link node, we decrement its occurrence count by the +  /// number of sequences we outlined in the current step. In the pathological +  /// example, the 2 3 node would have an occurrence count of 8, while the +  /// 1 2 3 node would have an occurrence count of 2. Thus, the 2 3 node +  /// would survive to the next round allowing us to outline the extra +  /// instances of 2 3. +  SuffixTreeNode *Link = nullptr; + +  /// The parent of this node. Every node except for the root has a parent. +  SuffixTreeNode *Parent = nullptr; + +  /// The number of times this node's string appears in the tree. +  /// +  /// This is equal to the number of leaf children of the string. It represents +  /// the number of suffixes that the node's string is a prefix of. +  size_t OccurrenceCount = 0; + +  /// The length of the string formed by concatenating the edge labels from the +  /// root to this node. +  size_t ConcatLen = 0; + +  /// Returns true if this node is a leaf. +  bool isLeaf() const { return SuffixIdx != EmptyIdx; } + +  /// Returns true if this node is the root of its owning \p SuffixTree. +  bool isRoot() const { return StartIdx == EmptyIdx; } + +  /// Return the number of elements in the substring associated with this node. +  size_t size() const { + +    // Is it the root? If so, it's the empty string so return 0. +    if (isRoot()) +      return 0; + +    assert(*EndIdx != EmptyIdx && "EndIdx is undefined!"); + +    // Size = the number of elements in the string. +    // For example, [0 1 2 3] has length 4, not 3. 3-0 = 3, so we have 3-0+1. +    return *EndIdx - StartIdx + 1; +  } + +  SuffixTreeNode(size_t StartIdx, size_t *EndIdx, SuffixTreeNode *Link, +                 SuffixTreeNode *Parent) +      : StartIdx(StartIdx), EndIdx(EndIdx), Link(Link), Parent(Parent) {} + +  SuffixTreeNode() {} +}; + +/// A data structure for fast substring queries. +/// +/// Suffix trees represent the suffixes of their input strings in their leaves. +/// A suffix tree is a type of compressed trie structure where each node +/// represents an entire substring rather than a single character. Each leaf +/// of the tree is a suffix. +/// +/// A suffix tree can be seen as a type of state machine where each state is a +/// substring of the full string. The tree is structured so that, for a string +/// of length N, there are exactly N leaves in the tree. This structure allows +/// us to quickly find repeated substrings of the input string. +/// +/// In this implementation, a "string" is a vector of unsigned integers. +/// These integers may result from hashing some data type. A suffix tree can +/// contain 1 or many strings, which can then be queried as one large string. +/// +/// The suffix tree is implemented using Ukkonen's algorithm for linear-time +/// suffix tree construction. Ukkonen's algorithm is explained in more detail +/// in the paper by Esko Ukkonen "On-line construction of suffix trees. The +/// paper is available at +/// +/// https://www.cs.helsinki.fi/u/ukkonen/SuffixT1withFigs.pdf +class SuffixTree { +private: +  /// Each element is an integer representing an instruction in the module. +  ArrayRef<unsigned> Str; + +  /// Maintains each node in the tree. +  SpecificBumpPtrAllocator<SuffixTreeNode> NodeAllocator; + +  /// The root of the suffix tree. +  /// +  /// The root represents the empty string. It is maintained by the +  /// \p NodeAllocator like every other node in the tree. +  SuffixTreeNode *Root = nullptr; + +  /// Stores each leaf node in the tree. +  /// +  /// This is used for finding outlining candidates. +  std::vector<SuffixTreeNode *> LeafVector; + +  /// Maintains the end indices of the internal nodes in the tree. +  /// +  /// Each internal node is guaranteed to never have its end index change +  /// during the construction algorithm; however, leaves must be updated at +  /// every step. Therefore, we need to store leaf end indices by reference +  /// to avoid updating O(N) leaves at every step of construction. Thus, +  /// every internal node must be allocated its own end index. +  BumpPtrAllocator InternalEndIdxAllocator; + +  /// The end index of each leaf in the tree. +  size_t LeafEndIdx = -1; + +  /// \brief Helper struct which keeps track of the next insertion point in +  /// Ukkonen's algorithm. +  struct ActiveState { +    /// The next node to insert at. +    SuffixTreeNode *Node; + +    /// The index of the first character in the substring currently being added. +    size_t Idx = EmptyIdx; + +    /// The length of the substring we have to add at the current step. +    size_t Len = 0; +  }; + +  /// \brief The point the next insertion will take place at in the +  /// construction algorithm. +  ActiveState Active; + +  /// Allocate a leaf node and add it to the tree. +  /// +  /// \param Parent The parent of this node. +  /// \param StartIdx The start index of this node's associated string. +  /// \param Edge The label on the edge leaving \p Parent to this node. +  /// +  /// \returns A pointer to the allocated leaf node. +  SuffixTreeNode *insertLeaf(SuffixTreeNode &Parent, size_t StartIdx, +                             unsigned Edge) { + +    assert(StartIdx <= LeafEndIdx && "String can't start after it ends!"); + +    SuffixTreeNode *N = new (NodeAllocator.Allocate()) SuffixTreeNode(StartIdx,  +                                                                   &LeafEndIdx, +                                                                       nullptr, +                                                                      &Parent); +    Parent.Children[Edge] = N; + +    return N; +  } + +  /// Allocate an internal node and add it to the tree. +  /// +  /// \param Parent The parent of this node. Only null when allocating the root. +  /// \param StartIdx The start index of this node's associated string. +  /// \param EndIdx The end index of this node's associated string. +  /// \param Edge The label on the edge leaving \p Parent to this node. +  /// +  /// \returns A pointer to the allocated internal node. +  SuffixTreeNode *insertInternalNode(SuffixTreeNode *Parent, size_t StartIdx, +                                     size_t EndIdx, unsigned Edge) { + +    assert(StartIdx <= EndIdx && "String can't start after it ends!"); +    assert(!(!Parent && StartIdx != EmptyIdx) && +    "Non-root internal nodes must have parents!"); + +    size_t *E = new (InternalEndIdxAllocator) size_t(EndIdx); +    SuffixTreeNode *N = new (NodeAllocator.Allocate()) SuffixTreeNode(StartIdx, +                                                                      E, +                                                                      Root, +                                                                      Parent); +    if (Parent) +      Parent->Children[Edge] = N; + +    return N; +  } + +  /// \brief Set the suffix indices of the leaves to the start indices of their +  /// respective suffixes. Also stores each leaf in \p LeafVector at its +  /// respective suffix index. +  /// +  /// \param[in] CurrNode The node currently being visited. +  /// \param CurrIdx The current index of the string being visited. +  void setSuffixIndices(SuffixTreeNode &CurrNode, size_t CurrIdx) { + +    bool IsLeaf = CurrNode.Children.size() == 0 && !CurrNode.isRoot(); + +    // Store the length of the concatenation of all strings from the root to +    // this node. +    if (!CurrNode.isRoot()) { +      if (CurrNode.ConcatLen == 0) +        CurrNode.ConcatLen = CurrNode.size(); + +      if (CurrNode.Parent) +       CurrNode.ConcatLen += CurrNode.Parent->ConcatLen; +    } + +    // Traverse the tree depth-first. +    for (auto &ChildPair : CurrNode.Children) { +      assert(ChildPair.second && "Node had a null child!"); +      setSuffixIndices(*ChildPair.second, +                       CurrIdx + ChildPair.second->size()); +    } + +    // Is this node a leaf? +    if (IsLeaf) { +      // If yes, give it a suffix index and bump its parent's occurrence count. +      CurrNode.SuffixIdx = Str.size() - CurrIdx; +      assert(CurrNode.Parent && "CurrNode had no parent!"); +      CurrNode.Parent->OccurrenceCount++; + +      // Store the leaf in the leaf vector for pruning later. +      LeafVector[CurrNode.SuffixIdx] = &CurrNode; +    } +  } + +  /// \brief Construct the suffix tree for the prefix of the input ending at +  /// \p EndIdx. +  /// +  /// Used to construct the full suffix tree iteratively. At the end of each +  /// step, the constructed suffix tree is either a valid suffix tree, or a +  /// suffix tree with implicit suffixes. At the end of the final step, the +  /// suffix tree is a valid tree. +  /// +  /// \param EndIdx The end index of the current prefix in the main string. +  /// \param SuffixesToAdd The number of suffixes that must be added +  /// to complete the suffix tree at the current phase. +  /// +  /// \returns The number of suffixes that have not been added at the end of +  /// this step. +  unsigned extend(size_t EndIdx, size_t SuffixesToAdd) { +    SuffixTreeNode *NeedsLink = nullptr; + +    while (SuffixesToAdd > 0) { +     +      // Are we waiting to add anything other than just the last character? +      if (Active.Len == 0) { +        // If not, then say the active index is the end index. +        Active.Idx = EndIdx; +      } + +      assert(Active.Idx <= EndIdx && "Start index can't be after end index!"); + +      // The first character in the current substring we're looking at. +      unsigned FirstChar = Str[Active.Idx]; + +      // Have we inserted anything starting with FirstChar at the current node? +      if (Active.Node->Children.count(FirstChar) == 0) { +        // If not, then we can just insert a leaf and move too the next step. +        insertLeaf(*Active.Node, EndIdx, FirstChar); + +        // The active node is an internal node, and we visited it, so it must +        // need a link if it doesn't have one. +        if (NeedsLink) { +          NeedsLink->Link = Active.Node; +          NeedsLink = nullptr; +        } +      } else { +        // There's a match with FirstChar, so look for the point in the tree to +        // insert a new node. +        SuffixTreeNode *NextNode = Active.Node->Children[FirstChar]; + +        size_t SubstringLen = NextNode->size(); + +        // Is the current suffix we're trying to insert longer than the size of +        // the child we want to move to? +        if (Active.Len >= SubstringLen) { +          // If yes, then consume the characters we've seen and move to the next +          // node. +          Active.Idx += SubstringLen; +          Active.Len -= SubstringLen; +          Active.Node = NextNode; +          continue; +        } + +        // Otherwise, the suffix we're trying to insert must be contained in the +        // next node we want to move to. +        unsigned LastChar = Str[EndIdx]; + +        // Is the string we're trying to insert a substring of the next node? +        if (Str[NextNode->StartIdx + Active.Len] == LastChar) { +          // If yes, then we're done for this step. Remember our insertion point +          // and move to the next end index. At this point, we have an implicit +          // suffix tree. +          if (NeedsLink && !Active.Node->isRoot()) { +            NeedsLink->Link = Active.Node; +            NeedsLink = nullptr; +          } + +          Active.Len++; +          break; +        } + +        // The string we're trying to insert isn't a substring of the next node, +        // but matches up to a point. Split the node. +        // +        // For example, say we ended our search at a node n and we're trying to +        // insert ABD. Then we'll create a new node s for AB, reduce n to just +        // representing C, and insert a new leaf node l to represent d. This +        // allows us to ensure that if n was a leaf, it remains a leaf. +        // +        //   | ABC  ---split--->  | AB +        //   n                    s +        //                     C / \ D +        //                      n   l + +        // The node s from the diagram +        SuffixTreeNode *SplitNode = +            insertInternalNode(Active.Node, +                               NextNode->StartIdx, +                               NextNode->StartIdx + Active.Len - 1, +                               FirstChar); + +        // Insert the new node representing the new substring into the tree as +        // a child of the split node. This is the node l from the diagram. +        insertLeaf(*SplitNode, EndIdx, LastChar); + +        // Make the old node a child of the split node and update its start +        // index. This is the node n from the diagram. +        NextNode->StartIdx += Active.Len; +        NextNode->Parent = SplitNode; +        SplitNode->Children[Str[NextNode->StartIdx]] = NextNode; + +        // SplitNode is an internal node, update the suffix link. +        if (NeedsLink) +          NeedsLink->Link = SplitNode; + +        NeedsLink = SplitNode; +      } + +      // We've added something new to the tree, so there's one less suffix to +      // add. +      SuffixesToAdd--; + +      if (Active.Node->isRoot()) { +        if (Active.Len > 0) { +          Active.Len--; +          Active.Idx = EndIdx - SuffixesToAdd + 1; +        } +      } else { +        // Start the next phase at the next smallest suffix. +        Active.Node = Active.Node->Link; +      } +    } + +    return SuffixesToAdd; +  } + +public: + +  /// Find all repeated substrings that satisfy \p BenefitFn. +  /// +  /// If a substring appears at least twice, then it must be represented by +  /// an internal node which appears in at least two suffixes. Each suffix is +  /// represented by a leaf node. To do this, we visit each internal node in +  /// the tree, using the leaf children of each internal node. If an internal +  /// node represents a beneficial substring, then we use each of its leaf +  /// children to find the locations of its substring. +  /// +  /// \param[out] CandidateList Filled with candidates representing each +  /// beneficial substring. +  /// \param[out] FunctionList Filled with a list of \p OutlinedFunctions each +  /// type of candidate. +  /// \param BenefitFn The function to satisfy. +  /// +  /// \returns The length of the longest candidate found. +  size_t findCandidates(std::vector<Candidate> &CandidateList, +  std::vector<OutlinedFunction> &FunctionList, +  const std::function<unsigned(SuffixTreeNode &, size_t, unsigned)> +  &BenefitFn) { + +    CandidateList.clear(); +    FunctionList.clear(); +    size_t FnIdx = 0; +    size_t MaxLen = 0; + +    for (SuffixTreeNode* Leaf : LeafVector) { +      assert(Leaf && "Leaves in LeafVector cannot be null!"); +      if (!Leaf->IsInTree) +        continue; + +      assert(Leaf->Parent && "All leaves must have parents!"); +      SuffixTreeNode &Parent = *(Leaf->Parent); + +      // If it doesn't appear enough, or we already outlined from it, skip it. +      if (Parent.OccurrenceCount < 2 || Parent.isRoot() || !Parent.IsInTree) +        continue; + +      size_t StringLen = Leaf->ConcatLen - Leaf->size(); + +      // How many instructions would outlining this string save? +      unsigned Benefit = BenefitFn(Parent, +        StringLen, Str[Leaf->SuffixIdx + StringLen - 1]); + +      // If it's not beneficial, skip it. +      if (Benefit < 1) +        continue; + +      if (StringLen > MaxLen) +        MaxLen = StringLen; + +      unsigned OccurrenceCount = 0; +      for (auto &ChildPair : Parent.Children) { +        SuffixTreeNode *M = ChildPair.second; + +        // Is it a leaf? If so, we have an occurrence of this candidate. +        if (M && M->IsInTree && M->isLeaf()) { +          OccurrenceCount++; +          CandidateList.emplace_back(M->SuffixIdx, StringLen, FnIdx); +          CandidateList.back().Benefit = Benefit; +          M->IsInTree = false; +        } +      } + +      // Save the function for the new candidate sequence. +      std::vector<unsigned> CandidateSequence; +      for (unsigned i = Leaf->SuffixIdx; i < Leaf->SuffixIdx + StringLen; i++) +        CandidateSequence.push_back(Str[i]); + +      FunctionList.emplace_back(FnIdx, OccurrenceCount, CandidateSequence, +                                Benefit, false); + +      // Move to the next function. +      FnIdx++; +      Parent.IsInTree = false; +    } + +    return MaxLen; +  } +  +  /// Construct a suffix tree from a sequence of unsigned integers. +  /// +  /// \param Str The string to construct the suffix tree for. +  SuffixTree(const std::vector<unsigned> &Str) : Str(Str) { +    Root = insertInternalNode(nullptr, EmptyIdx, EmptyIdx, 0); +    Root->IsInTree = true; +    Active.Node = Root; +    LeafVector = std::vector<SuffixTreeNode*>(Str.size()); + +    // Keep track of the number of suffixes we have to add of the current +    // prefix. +    size_t SuffixesToAdd = 0; +    Active.Node = Root; + +    // Construct the suffix tree iteratively on each prefix of the string. +    // PfxEndIdx is the end index of the current prefix. +    // End is one past the last element in the string. +    for (size_t PfxEndIdx = 0, End = Str.size(); PfxEndIdx < End; PfxEndIdx++) { +      SuffixesToAdd++; +      LeafEndIdx = PfxEndIdx; // Extend each of the leaves. +      SuffixesToAdd = extend(PfxEndIdx, SuffixesToAdd); +    } + +    // Set the suffix indices of each leaf. +    assert(Root && "Root node can't be nullptr!"); +    setSuffixIndices(*Root, 0); +  } +}; + +/// \brief Maps \p MachineInstrs to unsigned integers and stores the mappings. +struct InstructionMapper { + +  /// \brief The next available integer to assign to a \p MachineInstr that +  /// cannot be outlined. +  /// +  /// Set to -3 for compatability with \p DenseMapInfo<unsigned>. +  unsigned IllegalInstrNumber = -3; + +  /// \brief The next available integer to assign to a \p MachineInstr that can +  /// be outlined. +  unsigned LegalInstrNumber = 0; + +  /// Correspondence from \p MachineInstrs to unsigned integers. +  DenseMap<MachineInstr *, unsigned, MachineInstrExpressionTrait> +      InstructionIntegerMap; + +  /// Corresponcence from unsigned integers to \p MachineInstrs. +  /// Inverse of \p InstructionIntegerMap. +  DenseMap<unsigned, MachineInstr *> IntegerInstructionMap; + +  /// The vector of unsigned integers that the module is mapped to. +  std::vector<unsigned> UnsignedVec; + +  /// \brief Stores the location of the instruction associated with the integer +  /// at index i in \p UnsignedVec for each index i. +  std::vector<MachineBasicBlock::iterator> InstrList; + +  /// \brief Maps \p *It to a legal integer. +  /// +  /// Updates \p InstrList, \p UnsignedVec, \p InstructionIntegerMap, +  /// \p IntegerInstructionMap, and \p LegalInstrNumber. +  /// +  /// \returns The integer that \p *It was mapped to. +  unsigned mapToLegalUnsigned(MachineBasicBlock::iterator &It) { + +    // Get the integer for this instruction or give it the current +    // LegalInstrNumber. +    InstrList.push_back(It); +    MachineInstr &MI = *It; +    bool WasInserted; +    DenseMap<MachineInstr *, unsigned, MachineInstrExpressionTrait>::iterator +    ResultIt; +    std::tie(ResultIt, WasInserted) = +    InstructionIntegerMap.insert(std::make_pair(&MI, LegalInstrNumber)); +    unsigned MINumber = ResultIt->second; + +    // There was an insertion. +    if (WasInserted) { +      LegalInstrNumber++; +      IntegerInstructionMap.insert(std::make_pair(MINumber, &MI)); +    } + +    UnsignedVec.push_back(MINumber); + +    // Make sure we don't overflow or use any integers reserved by the DenseMap. +    if (LegalInstrNumber >= IllegalInstrNumber) +      report_fatal_error("Instruction mapping overflow!"); + +    assert(LegalInstrNumber != DenseMapInfo<unsigned>::getEmptyKey() +          && "Tried to assign DenseMap tombstone or empty key to instruction."); +    assert(LegalInstrNumber != DenseMapInfo<unsigned>::getTombstoneKey() +          && "Tried to assign DenseMap tombstone or empty key to instruction."); + +    return MINumber; +  } + +  /// Maps \p *It to an illegal integer. +  /// +  /// Updates \p InstrList, \p UnsignedVec, and \p IllegalInstrNumber. +  /// +  /// \returns The integer that \p *It was mapped to. +  unsigned mapToIllegalUnsigned(MachineBasicBlock::iterator &It) { +    unsigned MINumber = IllegalInstrNumber; + +    InstrList.push_back(It); +    UnsignedVec.push_back(IllegalInstrNumber); +    IllegalInstrNumber--; + +    assert(LegalInstrNumber < IllegalInstrNumber && +           "Instruction mapping overflow!"); + +    assert(IllegalInstrNumber != +      DenseMapInfo<unsigned>::getEmptyKey() && +      "IllegalInstrNumber cannot be DenseMap tombstone or empty key!"); + +    assert(IllegalInstrNumber != +      DenseMapInfo<unsigned>::getTombstoneKey() && +      "IllegalInstrNumber cannot be DenseMap tombstone or empty key!"); + +    return MINumber; +  } + +  /// \brief Transforms a \p MachineBasicBlock into a \p vector of \p unsigneds +  /// and appends it to \p UnsignedVec and \p InstrList. +  /// +  /// Two instructions are assigned the same integer if they are identical. +  /// If an instruction is deemed unsafe to outline, then it will be assigned an +  /// unique integer. The resulting mapping is placed into a suffix tree and +  /// queried for candidates. +  /// +  /// \param MBB The \p MachineBasicBlock to be translated into integers. +  /// \param TRI \p TargetRegisterInfo for the module. +  /// \param TII \p TargetInstrInfo for the module. +  void convertToUnsignedVec(MachineBasicBlock &MBB, +                            const TargetRegisterInfo &TRI, +                            const TargetInstrInfo &TII) { +    for (MachineBasicBlock::iterator It = MBB.begin(), Et = MBB.end(); It != Et; +         It++) { + +      // Keep track of where this instruction is in the module. +      switch(TII.getOutliningType(*It)) { +        case TargetInstrInfo::MachineOutlinerInstrType::Illegal: +          mapToIllegalUnsigned(It); +          break; + +        case TargetInstrInfo::MachineOutlinerInstrType::Legal: +          mapToLegalUnsigned(It); +          break; + +        case TargetInstrInfo::MachineOutlinerInstrType::Invisible: +          break; +      } +    } + +    // After we're done every insertion, uniquely terminate this part of the +    // "string". This makes sure we won't match across basic block or function +    // boundaries since the "end" is encoded uniquely and thus appears in no +    // repeated substring. +    InstrList.push_back(MBB.end()); +    UnsignedVec.push_back(IllegalInstrNumber); +    IllegalInstrNumber--; +  } + +  InstructionMapper() { +    // Make sure that the implementation of DenseMapInfo<unsigned> hasn't +    // changed. +    assert(DenseMapInfo<unsigned>::getEmptyKey() == (unsigned)-1 && +                "DenseMapInfo<unsigned>'s empty key isn't -1!"); +    assert(DenseMapInfo<unsigned>::getTombstoneKey() == (unsigned)-2 && +                "DenseMapInfo<unsigned>'s tombstone key isn't -2!"); +  } +}; + +/// \brief An interprocedural pass which finds repeated sequences of +/// instructions and replaces them with calls to functions. +/// +/// Each instruction is mapped to an unsigned integer and placed in a string. +/// The resulting mapping is then placed in a \p SuffixTree. The \p SuffixTree +/// is then repeatedly queried for repeated sequences of instructions. Each +/// non-overlapping repeated sequence is then placed in its own +/// \p MachineFunction and each instance is then replaced with a call to that +/// function. +struct MachineOutliner : public ModulePass { + +  static char ID; + +  StringRef getPassName() const override { return "Machine Outliner"; } + +  void getAnalysisUsage(AnalysisUsage &AU) const override { +    AU.addRequired<MachineModuleInfo>(); +    AU.addPreserved<MachineModuleInfo>(); +    AU.setPreservesAll(); +    ModulePass::getAnalysisUsage(AU); +  } + +  MachineOutliner() : ModulePass(ID) { +    initializeMachineOutlinerPass(*PassRegistry::getPassRegistry()); +  } + +  /// \brief Replace the sequences of instructions represented by the +  /// \p Candidates in \p CandidateList with calls to \p MachineFunctions +  /// described in \p FunctionList. +  /// +  /// \param M The module we are outlining from. +  /// \param CandidateList A list of candidates to be outlined. +  /// \param FunctionList A list of functions to be inserted into the module. +  /// \param Mapper Contains the instruction mappings for the module. +  bool outline(Module &M, const ArrayRef<Candidate> &CandidateList, +               std::vector<OutlinedFunction> &FunctionList, +               InstructionMapper &Mapper); + +  /// Creates a function for \p OF and inserts it into the module. +  MachineFunction *createOutlinedFunction(Module &M, const OutlinedFunction &OF, +                                          InstructionMapper &Mapper); + +  /// Find potential outlining candidates and store them in \p CandidateList. +  /// +  /// For each type of potential candidate, also build an \p OutlinedFunction +  /// struct containing the information to build the function for that +  /// candidate. +  /// +  /// \param[out] CandidateList Filled with outlining candidates for the module. +  /// \param[out] FunctionList Filled with functions corresponding to each type +  /// of \p Candidate. +  /// \param ST The suffix tree for the module. +  /// \param TII TargetInstrInfo for the module. +  /// +  /// \returns The length of the longest candidate found. 0 if there are none. +  unsigned buildCandidateList(std::vector<Candidate> &CandidateList, +                              std::vector<OutlinedFunction> &FunctionList, +                              SuffixTree &ST, +                              InstructionMapper &Mapper, +                              const TargetInstrInfo &TII); + +  /// \brief Remove any overlapping candidates that weren't handled by the +  /// suffix tree's pruning method. +  /// +  /// Pruning from the suffix tree doesn't necessarily remove all overlaps. +  /// If a short candidate is chosen for outlining, then a longer candidate +  /// which has that short candidate as a suffix is chosen, the tree's pruning +  /// method will not find it. Thus, we need to prune before outlining as well. +  /// +  /// \param[in,out] CandidateList A list of outlining candidates. +  /// \param[in,out] FunctionList A list of functions to be outlined. +  /// \param MaxCandidateLen The length of the longest candidate. +  /// \param TII TargetInstrInfo for the module. +  void pruneOverlaps(std::vector<Candidate> &CandidateList, +                     std::vector<OutlinedFunction> &FunctionList, +                     unsigned MaxCandidateLen, +                     const TargetInstrInfo &TII); + +  /// Construct a suffix tree on the instructions in \p M and outline repeated +  /// strings from that tree. +  bool runOnModule(Module &M) override; +}; + +} // Anonymous namespace. + +char MachineOutliner::ID = 0; + +namespace llvm { +ModulePass *createMachineOutlinerPass() { return new MachineOutliner(); } +} + +INITIALIZE_PASS(MachineOutliner, "machine-outliner", +                "Machine Function Outliner", false, false) + +void MachineOutliner::pruneOverlaps(std::vector<Candidate> &CandidateList, +                                    std::vector<OutlinedFunction> &FunctionList, +                                    unsigned MaxCandidateLen, +                                    const TargetInstrInfo &TII) { +  // TODO: Experiment with interval trees or other interval-checking structures +  // to lower the time complexity of this function. +  // TODO: Can we do better than the simple greedy choice? +  // Check for overlaps in the range. +  // This is O(MaxCandidateLen * CandidateList.size()). +  for (auto It = CandidateList.begin(), Et = CandidateList.end(); It != Et; +       It++) { +    Candidate &C1 = *It; +    OutlinedFunction &F1 = FunctionList[C1.FunctionIdx]; + +    // If we removed this candidate, skip it. +    if (!C1.InCandidateList) +      continue; + +    // Is it still worth it to outline C1? +    if (F1.Benefit < 1 || F1.OccurrenceCount < 2) { +      assert(F1.OccurrenceCount > 0 && +               "Can't remove OutlinedFunction with no occurrences!"); +      F1.OccurrenceCount--; +      C1.InCandidateList = false; +      continue; +    } + +    // The minimum start index of any candidate that could overlap with this +    // one. +    unsigned FarthestPossibleIdx = 0; + +    // Either the index is 0, or it's at most MaxCandidateLen indices away. +    if (C1.StartIdx > MaxCandidateLen) +      FarthestPossibleIdx = C1.StartIdx - MaxCandidateLen; + +    // Compare against the candidates in the list that start at at most +    // FarthestPossibleIdx indices away from C1. There are at most +    // MaxCandidateLen of these. +    for (auto Sit = It + 1; Sit != Et; Sit++) { +      Candidate &C2 = *Sit; +      OutlinedFunction &F2 = FunctionList[C2.FunctionIdx]; + +      // Is this candidate too far away to overlap? +      if (C2.StartIdx < FarthestPossibleIdx) +        break; + +      // Did we already remove this candidate in a previous step? +      if (!C2.InCandidateList) +        continue; + +      // Is the function beneficial to outline? +      if (F2.OccurrenceCount < 2 || F2.Benefit < 1) { +        // If not, remove this candidate and move to the next one. +        assert(F2.OccurrenceCount > 0 && +               "Can't remove OutlinedFunction with no occurrences!"); +        F2.OccurrenceCount--; +        C2.InCandidateList = false; +        continue; +      } + +      size_t C2End = C2.StartIdx + C2.Len - 1; + +      // Do C1 and C2 overlap? +      // +      // Not overlapping: +      // High indices... [C1End ... C1Start][C2End ... C2Start] ...Low indices +      // +      // We sorted our candidate list so C2Start <= C1Start. We know that +      // C2End > C2Start since each candidate has length >= 2. Therefore, all we +      // have to check is C2End < C2Start to see if we overlap. +      if (C2End < C1.StartIdx) +        continue; + +      // C1 and C2 overlap. +      // We need to choose the better of the two. +      // +      // Approximate this by picking the one which would have saved us the +      // most instructions before any pruning. +      if (C1.Benefit >= C2.Benefit) { + +        // C1 is better, so remove C2 and update C2's OutlinedFunction to +        // reflect the removal. +        assert(F2.OccurrenceCount > 0 && +               "Can't remove OutlinedFunction with no occurrences!"); +        F2.OccurrenceCount--; +        F2.Benefit = TII.getOutliningBenefit(F2.Sequence.size(), +                                             F2.OccurrenceCount, +                                             F2.IsTailCall +                                             ); + +        C2.InCandidateList = false; + +        DEBUG ( +          dbgs() << "- Removed C2. \n"; +          dbgs() << "--- Num fns left for C2: " << F2.OccurrenceCount << "\n"; +          dbgs() << "--- C2's benefit: " << F2.Benefit << "\n"; +        ); + +      } else { +        // C2 is better, so remove C1 and update C1's OutlinedFunction to +        // reflect the removal. +        assert(F1.OccurrenceCount > 0 && +               "Can't remove OutlinedFunction with no occurrences!"); +        F1.OccurrenceCount--; +        F1.Benefit = TII.getOutliningBenefit(F1.Sequence.size(), +                                             F1.OccurrenceCount, +                                             F1.IsTailCall +                                             ); +        C1.InCandidateList = false; + +        DEBUG ( +          dbgs() << "- Removed C1. \n"; +          dbgs() << "--- Num fns left for C1: " << F1.OccurrenceCount << "\n"; +          dbgs() << "--- C1's benefit: " << F1.Benefit << "\n"; +        ); + +        // C1 is out, so we don't have to compare it against anyone else. +        break; +      } +    } +  } +} + +unsigned +MachineOutliner::buildCandidateList(std::vector<Candidate> &CandidateList, +                                    std::vector<OutlinedFunction> &FunctionList, +                                    SuffixTree &ST, +                                    InstructionMapper &Mapper, +                                    const TargetInstrInfo &TII) { + +  std::vector<unsigned> CandidateSequence; // Current outlining candidate. +  size_t MaxCandidateLen = 0; // Length of the longest candidate. + +  // Function for maximizing query in the suffix tree. +  // This allows us to define more fine-grained types of things to outline in +  // the target without putting target-specific info in the suffix tree. +  auto BenefitFn = [&TII, &Mapper](const SuffixTreeNode &Curr, +                                   size_t StringLen, unsigned EndVal) { + +    // The root represents the empty string. +    if (Curr.isRoot()) +      return 0u; + +    // Is this long enough to outline? +	// TODO: Let the target decide how "long" a string is in terms of the sizes +	// of the instructions in the string. For example, if a call instruction +	// is smaller than a one instruction string, we should outline that string. +    if (StringLen < 2) +      return 0u; + +    size_t Occurrences = Curr.OccurrenceCount; + +    // Anything we want to outline has to appear at least twice. +    if (Occurrences < 2) +      return 0u; + +    // Check if the last instruction in the sequence is a return. +    MachineInstr *LastInstr = +    Mapper.IntegerInstructionMap[EndVal]; +    assert(LastInstr && "Last instruction in sequence was unmapped!"); + +    // The only way a terminator could be mapped as legal is if it was safe to +    // tail call. +    bool IsTailCall = LastInstr->isTerminator(); +    return TII.getOutliningBenefit(StringLen, Occurrences, IsTailCall); +  }; + +  MaxCandidateLen = ST.findCandidates(CandidateList, FunctionList, BenefitFn); + +  for (auto &OF : FunctionList) +    OF.IsTailCall = Mapper. +                    IntegerInstructionMap[OF.Sequence.back()]->isTerminator(); + +  // Sort the candidates in decending order. This will simplify the outlining +  // process when we have to remove the candidates from the mapping by +  // allowing us to cut them out without keeping track of an offset. +  std::stable_sort(CandidateList.begin(), CandidateList.end()); + +  return MaxCandidateLen; +} + +MachineFunction * +MachineOutliner::createOutlinedFunction(Module &M, const OutlinedFunction &OF, +  InstructionMapper &Mapper) { + +  // Create the function name. This should be unique. For now, just hash the +  // module name and include it in the function name plus the number of this +  // function. +  std::ostringstream NameStream; +  NameStream << "OUTLINED_FUNCTION" << "_" << OF.Name; + +  // Create the function using an IR-level function. +  LLVMContext &C = M.getContext(); +  Function *F = dyn_cast<Function>( +      M.getOrInsertFunction(NameStream.str(), Type::getVoidTy(C))); +  assert(F && "Function was null!"); + +  // NOTE: If this is linkonceodr, then we can take advantage of linker deduping +  // which gives us better results when we outline from linkonceodr functions. +  F->setLinkage(GlobalValue::PrivateLinkage); +  F->setUnnamedAddr(GlobalValue::UnnamedAddr::Global); + +  BasicBlock *EntryBB = BasicBlock::Create(C, "entry", F); +  IRBuilder<> Builder(EntryBB); +  Builder.CreateRetVoid(); + +  MachineModuleInfo &MMI = getAnalysis<MachineModuleInfo>(); +  MachineFunction &MF = MMI.getMachineFunction(*F); +  MachineBasicBlock &MBB = *MF.CreateMachineBasicBlock(); +  const TargetSubtargetInfo &STI = MF.getSubtarget(); +  const TargetInstrInfo &TII = *STI.getInstrInfo(); + +  // Insert the new function into the module. +  MF.insert(MF.begin(), &MBB); + +  TII.insertOutlinerPrologue(MBB, MF, OF.IsTailCall); + +  // Copy over the instructions for the function using the integer mappings in +  // its sequence. +  for (unsigned Str : OF.Sequence) { +    MachineInstr *NewMI = +        MF.CloneMachineInstr(Mapper.IntegerInstructionMap.find(Str)->second); +    NewMI->dropMemRefs(); + +    // Don't keep debug information for outlined instructions. +    // FIXME: This means outlined functions are currently undebuggable. +    NewMI->setDebugLoc(DebugLoc()); +    MBB.insert(MBB.end(), NewMI); +  } + +  TII.insertOutlinerEpilogue(MBB, MF, OF.IsTailCall); + +  return &MF; +} + +bool MachineOutliner::outline(Module &M, +                              const ArrayRef<Candidate> &CandidateList, +                              std::vector<OutlinedFunction> &FunctionList, +                              InstructionMapper &Mapper) { + +  bool OutlinedSomething = false; + +  // Replace the candidates with calls to their respective outlined functions. +  for (const Candidate &C : CandidateList) { + +    // Was the candidate removed during pruneOverlaps? +    if (!C.InCandidateList) +      continue; + +    // If not, then look at its OutlinedFunction. +    OutlinedFunction &OF = FunctionList[C.FunctionIdx]; + +    // Was its OutlinedFunction made unbeneficial during pruneOverlaps? +    if (OF.OccurrenceCount < 2 || OF.Benefit < 1) +      continue; + +    // If not, then outline it. +    assert(C.StartIdx < Mapper.InstrList.size() && "Candidate out of bounds!"); +    MachineBasicBlock *MBB = (*Mapper.InstrList[C.StartIdx]).getParent(); +    MachineBasicBlock::iterator StartIt = Mapper.InstrList[C.StartIdx]; +    unsigned EndIdx = C.StartIdx + C.Len - 1; + +    assert(EndIdx < Mapper.InstrList.size() && "Candidate out of bounds!"); +    MachineBasicBlock::iterator EndIt = Mapper.InstrList[EndIdx]; +    assert(EndIt != MBB->end() && "EndIt out of bounds!"); + +    EndIt++; // Erase needs one past the end index. + +    // Does this candidate have a function yet? +    if (!OF.MF) { +      OF.MF = createOutlinedFunction(M, OF, Mapper); +      FunctionsCreated++; +    } + +    MachineFunction *MF = OF.MF; +    const TargetSubtargetInfo &STI = MF->getSubtarget(); +    const TargetInstrInfo &TII = *STI.getInstrInfo(); + +    // Insert a call to the new function and erase the old sequence. +    TII.insertOutlinedCall(M, *MBB, StartIt, *MF, OF.IsTailCall); +    StartIt = Mapper.InstrList[C.StartIdx]; +    MBB->erase(StartIt, EndIt); + +    OutlinedSomething = true; + +    // Statistics. +    NumOutlined++; +  } + +  DEBUG ( +    dbgs() << "OutlinedSomething = " << OutlinedSomething << "\n"; +  ); + +  return OutlinedSomething; +} + +bool MachineOutliner::runOnModule(Module &M) { + +  // Is there anything in the module at all? +  if (M.empty()) +    return false; + +  MachineModuleInfo &MMI = getAnalysis<MachineModuleInfo>(); +  const TargetSubtargetInfo &STI = MMI.getMachineFunction(*M.begin()) +                                      .getSubtarget(); +  const TargetRegisterInfo *TRI = STI.getRegisterInfo(); +  const TargetInstrInfo *TII = STI.getInstrInfo(); + +  InstructionMapper Mapper; + +  // Build instruction mappings for each function in the module. +  for (Function &F : M) { +    MachineFunction &MF = MMI.getMachineFunction(F); + +    // Is the function empty? Safe to outline from? +    if (F.empty() || !TII->isFunctionSafeToOutlineFrom(MF)) +      continue; + +    // If it is, look at each MachineBasicBlock in the function. +    for (MachineBasicBlock &MBB : MF) { + +      // Is there anything in MBB? +      if (MBB.empty()) +        continue; + +      // If yes, map it. +      Mapper.convertToUnsignedVec(MBB, *TRI, *TII); +    } +  } + +  // Construct a suffix tree, use it to find candidates, and then outline them. +  SuffixTree ST(Mapper.UnsignedVec); +  std::vector<Candidate> CandidateList; +  std::vector<OutlinedFunction> FunctionList; + +  // Find all of the outlining candidates. +  unsigned MaxCandidateLen = +      buildCandidateList(CandidateList, FunctionList, ST, Mapper, *TII); + +  // Remove candidates that overlap with other candidates. +  pruneOverlaps(CandidateList, FunctionList, MaxCandidateLen, *TII); + +  // Outline each of the candidates and return true if something was outlined. +  return outline(M, CandidateList, FunctionList, Mapper); +}  | 
