diff options
Diffstat (limited to 'src/plugins/kdb/db2/libdb2/test/run.test')
| -rw-r--r-- | src/plugins/kdb/db2/libdb2/test/run.test | 1034 |
1 files changed, 1034 insertions, 0 deletions
diff --git a/src/plugins/kdb/db2/libdb2/test/run.test b/src/plugins/kdb/db2/libdb2/test/run.test new file mode 100644 index 000000000000..8d9225706a11 --- /dev/null +++ b/src/plugins/kdb/db2/libdb2/test/run.test @@ -0,0 +1,1034 @@ +#!/bin/sh - +# +# @(#)run.test 8.13 (Berkeley) 11/2/95 +# + +# db regression tests +main() +{ + + PROG=./dbtest + TMP1=${TMPDIR-.}/t1 + TMP2=${TMPDIR-.}/t2 + TMP3=${TMPDIR-.}/t3 + BINFILES=${TMPDIR-.}/binfiles + + if [ \! -z "$WORDLIST" -a -f "$WORDLIST" ]; then + DICT=$WORDLIST + elif [ -f /usr/local/lib/dict/words ]; then + DICT=/usr/local/lib/dict/words + elif [ -f /usr/share/dict/words ]; then + DICT=/usr/share/dict/words + elif [ -f /usr/dict/words ]; then + DICT=/usr/dict/words + elif [ -f /usr/share/lib/dict/words ]; then + DICT=/usr/share/lib/dict/words + elif [ -f $srcdir/../test/dictionary ]; then + DICT=`cd $srcdir/../test && pwd`/dictionary + else + echo 'run.test: no dictionary' + exit 1 + fi + + dictsize=`wc -l < $DICT` + + bindir=/bin/. + find $bindir -type f -exec test -r {} \; -print | head -100 > $BINFILES + + if [ $# -eq 0 ]; then + for t in 1 2 3 4 5 6 7 8 9 10 11 12 13 20 40 41 50 60 61 62 63; do + test$t + done + else + while [ $# -gt 0 ] + do case "$1" in + test*) + $1;; + [0-9]*) + test$1;; + btree) + for t in 1 2 3 7 8 9 10 12 13 40 41 50 60 61 62 63; do + test$t + done;; + hash) + for t in 1 2 3 8 13 20; do + test$t + done;; + recno) + for t in 1 2 3 4 5 6 7 10 11; do + test$t + done;; + *) + echo "run.test: unknown test $1" + echo "usage: run.test test# | type" + exit 1 + esac + shift + done + fi + rm -f $TMP1 $TMP2 $TMP3 $BINFILES + exit 0 +} + +getnwords() { + # Delete blank lines because the db code appears not to like + # empty keys. Omit lines with non-alphanumeric characters to + # avoid shell metacharacters and non-ASCII characters which + # could cause 'rev' to choke. + LC_ALL=C sed -e '/^$/d' -e '/[^A-Za-z]/d' < $DICT | sed -e ${1}q +} + +# Take the first hundred entries in the dictionary, and make them +# be key/data pairs. +test1() +{ + echo "Test 1: btree, hash: small key, small data pairs" + getnwords 200 > $TMP1 + for type in btree hash; do + rm -f $TMP2 $TMP3 + for i in `cat $TMP1`; do + echo p + echo k$i + echo d$i + echo g + echo k$i + done > $TMP2 + $PROG -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test1: type $type: failed" + exit 1 + fi + done + echo "Test 1: recno: small key, small data pairs" + rm -f $TMP2 $TMP3 + awk '{ + ++i; + printf("p\nk%d\nd%s\ng\nk%d\n", i, $0, i); + }' < $TMP1 > $TMP2 + $PROG -o $TMP3 recno $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test1: type recno: failed" + exit 1 + fi +} + +# Take the first 200 entries in the dictionary, and give them +# each a medium size data entry. +test2() +{ + echo "Test 2: btree, hash: small key, medium data pairs" + mdata=abcdefghijklmnopqrstuvwxyzabcdefghijklmnopqrstuvwxyz + echo $mdata | + awk '{ for (i = 1; i < 201; ++i) print $0 }' > $TMP1 + for type in hash btree; do + rm -f $TMP2 $TMP3 + for i in `getnwords 200`; do + echo p + echo k$i + echo d$mdata + echo g + echo k$i + done > $TMP2 + $PROG -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test2: type $type: failed" + exit 1 + fi + done + echo "Test 2: recno: small key, medium data pairs" + rm -f $TMP2 $TMP3 + echo $mdata | + awk '{ for (i = 1; i < 201; ++i) + printf("p\nk%d\nd%s\ng\nk%d\n", i, $0, i); + }' > $TMP2 + $PROG -o $TMP3 recno $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test2: type recno: failed" + exit 1 + fi +} + +# Insert the programs in $bindir with their paths as their keys. +test3() +{ + echo "Test 3: hash: small key, big data pairs" + rm -f $TMP1 + xargs cat < $BINFILES > $TMP1 + for type in hash; do + rm -f $TMP2 $TMP3 + for i in `cat $BINFILES`; do + echo p + echo k$i + echo D$i + echo g + echo k$i + done > $TMP2 + $PROG -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test3: $type: failed" + exit 1 + fi + done + echo "Test 3: btree: small key, big data pairs" + for psize in 512 16384 65536; do + echo " page size $psize" + for type in btree; do + rm -f $TMP2 $TMP3 + for i in `cat $BINFILES`; do + echo p + echo k$i + echo D$i + echo g + echo k$i + done > $TMP2 + $PROG -i psize=$psize -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test3: $type: page size $psize: failed" + exit 1 + fi + done + done + echo "Test 3: recno: big data pairs" + rm -f $TMP2 $TMP3 + awk '{ + ++i; + printf("p\nk%d\nD%s\ng\nk%d\n", i, $0, i); + }' < $BINFILES > $TMP2 + for psize in 512 16384 65536; do + echo " page size $psize" + $PROG -i psize=$psize -o $TMP3 recno $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test3: recno: page size $psize: failed" + exit 1 + fi + done +} + +# Do random recno entries. +test4() +{ + echo "Test 4: recno: random entries" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk '{ + for (i = 37; i <= 37 + 88 * 17; i += 17) { + if (i % 41) + s = substr($0, 1, i % 41); + else + s = substr($0, 1); + printf("input key %d: %s\n", i, s); + } + for (i = 1; i <= 15; ++i) { + if (i % 41) + s = substr($0, 1, i % 41); + else + s = substr($0, 1); + printf("input key %d: %s\n", i, s); + } + for (i = 19234; i <= 19234 + 61 * 27; i += 27) { + if (i % 41) + s = substr($0, 1, i % 41); + else + s = substr($0, 1); + printf("input key %d: %s\n", i, s); + } + exit + }' > $TMP1 + rm -f $TMP2 $TMP3 + cat $TMP1 | + awk 'BEGIN { + i = 37; + incr = 17; + } + { + printf("p\nk%d\nd%s\n", i, $0); + if (i == 19234 + 61 * 27) + exit; + if (i == 37 + 88 * 17) { + i = 1; + incr = 1; + } else if (i == 15) { + i = 19234; + incr = 27; + } else + i += incr; + } + END { + for (i = 37; i <= 37 + 88 * 17; i += 17) + printf("g\nk%d\n", i); + for (i = 1; i <= 15; ++i) + printf("g\nk%d\n", i); + for (i = 19234; i <= 19234 + 61 * 27; i += 27) + printf("g\nk%d\n", i); + }' > $TMP2 + $PROG -o $TMP3 recno $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test4: type recno: failed" + exit 1 + fi +} + +# Do reverse order recno entries. +test5() +{ + echo "Test 5: recno: reverse order entries" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk ' { + for (i = 1500; i; --i) { + if (i % 34) + s = substr($0, 1, i % 34); + else + s = substr($0, 1); + printf("input key %d: %s\n", i, s); + } + exit; + }' > $TMP1 + rm -f $TMP2 $TMP3 + cat $TMP1 | + awk 'BEGIN { + i = 1500; + } + { + printf("p\nk%d\nd%s\n", i, $0); + --i; + } + END { + for (i = 1500; i; --i) + printf("g\nk%d\n", i); + }' > $TMP2 + $PROG -o $TMP3 recno $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test5: type recno: failed" + exit 1 + fi +} + +# Do alternating order recno entries. +test6() +{ + echo "Test 6: recno: alternating order entries" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk ' { + for (i = 1; i < 1200; i += 2) { + if (i % 34) + s = substr($0, 1, i % 34); + else + s = substr($0, 1); + printf("input key %d: %s\n", i, s); + } + for (i = 2; i < 1200; i += 2) { + if (i % 34) + s = substr($0, 1, i % 34); + else + s = substr($0, 1); + printf("input key %d: %s\n", i, s); + } + exit; + }' > $TMP1 + rm -f $TMP2 $TMP3 + cat $TMP1 | + awk 'BEGIN { + i = 1; + even = 0; + } + { + printf("p\nk%d\nd%s\n", i, $0); + i += 2; + if (i >= 1200) { + if (even == 1) + exit; + even = 1; + i = 2; + } + } + END { + for (i = 1; i < 1200; ++i) + printf("g\nk%d\n", i); + }' > $TMP2 + $PROG -o $TMP3 recno $TMP2 + sort -o $TMP1 $TMP1 + sort -o $TMP3 $TMP3 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test6: type recno: failed" + exit 1 + fi +} + +# Delete cursor record +test7() +{ + echo "Test 7: btree, recno: delete cursor record" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk '{ + for (i = 1; i <= 120; ++i) + printf("%05d: input key %d: %s\n", i, i, $0); + printf("%05d: input key %d: %s\n", 120, 120, $0); + printf("seq failed, no such key\n"); + printf("%05d: input key %d: %s\n", 1, 1, $0); + printf("%05d: input key %d: %s\n", 2, 2, $0); + exit; + }' > $TMP1 + rm -f $TMP2 $TMP3 + + for type in btree recno; do + cat $TMP1 | + awk '{ + if (i == 120) + exit; + printf("p\nk%d\nd%s\n", ++i, $0); + } + END { + printf("fR_NEXT\n"); + for (i = 1; i <= 120; ++i) + printf("s\n"); + printf("fR_CURSOR\ns\nk120\n"); + printf("r\n"); + printf("fR_NEXT\ns\n"); + printf("fR_CURSOR\ns\nk1\n"); + printf("r\n"); + printf("fR_FIRST\ns\n"); + }' > $TMP2 + $PROG -o $TMP3 recno $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test7: type $type: failed" + exit 1 + fi + done +} + +# Make sure that overflow pages are reused. +test8() +{ + echo "Test 8: btree: repeated small key, big data pairs" + rm -f $TMP1 + # /bin/csh is no longer ubiquitous - find a substitute + # The test stores contents of a known file + tfile="" + for tp in /bin/csh /bin/ls /usr/bin/ls /bin/cat /usr/bin/cat; do + if [ "x$tfile" = "x" -a -f $tp ]; then + tfile=$tp + fi + done + if [ "x$tfile" = "x" ]; then + echo "No suitable file for testing purposes" + exit 1 + fi + echo "" | + awk 'BEGIN { + for (i = 1; i <= 10; ++i) { + printf("p\nkkey1\nD/bin/sh\n"); + printf("p\nkkey2\nD'$tfile'\n"); + if (i % 8 == 0) { + printf("c\nkkey2\nD'$tfile'\n"); + printf("c\nkkey1\nD/bin/sh\n"); + printf("e\t%d of 10 (comparison)\n", i); + } else + printf("e\t%d of 10 \n", i); + printf("r\nkkey1\nr\nkkey2\n"); + } + }' > $TMP1 + if $PROG btree $TMP1 ; then + true + else + echo "test8: btree tests failed" + exit 1 + fi +# $PROG hash $TMP1 + # No explicit test for success. +} + +# Test btree duplicate keys +test9() +{ + echo "Test 9: btree: duplicate keys" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk '{ + for (i = 1; i <= 543; ++i) + printf("%05d: input key %d: %s\n", i, i, $0); + exit; + }' > $TMP1 + rm -f $TMP2 $TMP3 + + for type in btree; do + cat $TMP1 | + awk '{ + if (i++ % 2) + printf("p\nkduplicatekey\nd%s\n", $0); + else + printf("p\nkunique%dkey\nd%s\n", i, $0); + } + END { + printf("o\n"); + }' > $TMP2 + $PROG -iflags=1 -o $TMP3 $type $TMP2 + sort -o $TMP3 $TMP3 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test9: type $type: failed" + exit 1 + fi + done +} + +# Test use of cursor flags without initialization +test10() +{ + echo "Test 10: btree, recno: test cursor flag use" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk '{ + for (i = 1; i <= 20; ++i) + printf("%05d: input key %d: %s\n", i, i, $0); + exit; + }' > $TMP1 + rm -f $TMP2 $TMP3 + + # Test that R_CURSOR doesn't succeed before cursor initialized + for type in btree recno; do + cat $TMP1 | + awk '{ + if (i == 10) + exit; + printf("p\nk%d\nd%s\n", ++i, $0); + } + END { + printf("fR_CURSOR\nr\n"); + printf("eR_CURSOR SHOULD HAVE FAILED\n"); + }' > $TMP2 + $PROG -o $TMP3 $type $TMP2 > /dev/null 2>&1 + if [ -s $TMP3 ] ; then + echo "Test 10: delete: R_CURSOR SHOULD HAVE FAILED" + exit 1 + fi + done + for type in btree recno; do + cat $TMP1 | + awk '{ + if (i == 10) + exit; + printf("p\nk%d\nd%s\n", ++i, $0); + } + END { + printf("fR_CURSOR\np\nk1\ndsome data\n"); + printf("eR_CURSOR SHOULD HAVE FAILED\n"); + }' > $TMP2 + $PROG -o $TMP3 $type $TMP2 > /dev/null 2>&1 + if [ -s $TMP3 ] ; then + echo "Test 10: put: R_CURSOR SHOULD HAVE FAILED" + exit 1 + fi + done +} + +# Test insert in reverse order. +test11() +{ + echo "Test 11: recno: reverse order insert" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk '{ + for (i = 1; i <= 779; ++i) + printf("%05d: input key %d: %s\n", i, i, $0); + exit; + }' > $TMP1 + rm -f $TMP2 $TMP3 + + for type in recno; do + cat $TMP1 | + awk '{ + if (i == 0) { + i = 1; + printf("p\nk1\nd%s\n", $0); + printf("%s\n", "fR_IBEFORE"); + } else + printf("p\nk1\nd%s\n", $0); + } + END { + printf("or\n"); + }' > $TMP2 + $PROG -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test11: type $type: failed" + exit 1 + fi + done +} + +# Take the first 20000 entries in the dictionary, reverse them, and give +# them each a small size data entry. Use a small page size to make sure +# the btree split code gets hammered. +test12() +{ + if ( rev < /dev/null ) > /dev/null 2>&1 ; then + : + else + echo "Test 12: skipped, rev not found" + return + fi + if test $dictsize -lt 20001 ; then + echo "Test 12: skipped, dictionary too small" + return + else + : + fi + echo "Test 12: btree: lots of keys, small page size" + mdata=abcdefghijklmnopqrstuvwxy + echo $mdata | + awk '{ for (i = 1; i < 20001; ++i) print $0 }' > $TMP1 + for type in btree; do + rm -f $TMP2 $TMP3 + for i in `getnwords 20000 | rev`; do + echo p + echo k$i + echo d$mdata + echo g + echo k$i + done > $TMP2 + $PROG -i psize=512 -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test12: type $type: failed" + exit 1 + fi + done +} + +# Test different byte orders. +test13() +{ + echo "Test 13: btree, hash: differing byte orders" + getnwords 50 > $TMP1 + for order in 1234 4321; do + for type in btree hash; do + rm -f byte.file $TMP2 $TMP3 + for i in `cat $TMP1`; do + echo p + echo k$i + echo d$i + echo S + echo g + echo k$i + done > $TMP2 + $PROG -ilorder=$order -f byte.file -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test13: $type/$order put failed" + exit 1 + fi + for i in `cat $TMP1`; do + echo g + echo k$i + done > $TMP2 + $PROG -s \ + -ilorder=$order -f byte.file -o $TMP3 $type $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test13: $type/$order get failed" + exit 1 + fi + done + done + rm -f byte.file +} + +# Try a variety of bucketsizes and fill factors for hashing +test20() +{ + if test $dictsize -lt 10001 ; then + echo "Test 20: skipped, dictionary too small" + return + else + : + fi + echo\ + "Test 20: hash: bucketsize, fill factor; nelem 25000 cachesize 65536" + echo "abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" | + awk '{ + for (i = 1; i <= 10000; ++i) { + if (i % 34) + s = substr($0, 1, i % 34); + else + s = substr($0, 1); + printf("%s\n", s); + } + exit; + }' > $TMP1 + getnwords 10000 | + awk 'BEGIN { + ds="abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg abcdefg" + } + { + if (++i % 34) + s = substr(ds, 1, i % 34); + else + s = substr(ds, 1); + printf("p\nk%s\nd%s\n", $0, s); + }' > $TMP2 + getnwords 10000 | + awk '{ + ++i; + printf("g\nk%s\n", $0); + }' >> $TMP2 + bsize=256 + for ffactor in 11 14 21; do + echo " bucketsize $bsize, fill factor $ffactor" + $PROG -o$TMP3 \ + -ibsize=$bsize,ffactor=$ffactor,nelem=25000,cachesize=65536\ + hash $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test20: type hash:\ +bsize=$bsize ffactor=$ffactor nelem=25000 cachesize=65536 failed" + exit 1 + fi + done + bsize=512 + for ffactor in 21 28 43; do + echo " bucketsize $bsize, fill factor $ffactor" + $PROG -o$TMP3 \ + -ibsize=$bsize,ffactor=$ffactor,nelem=25000,cachesize=65536\ + hash $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test20: type hash:\ +bsize=$bsize ffactor=$ffactor nelem=25000 cachesize=65536 failed" + exit 1 + fi + done + bsize=1024 + for ffactor in 43 57 85; do + echo " bucketsize $bsize, fill factor $ffactor" + $PROG -o$TMP3 \ + -ibsize=$bsize,ffactor=$ffactor,nelem=25000,cachesize=65536\ + hash $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test20: type hash:\ +bsize=$bsize ffactor=$ffactor nelem=25000 cachesize=65536 failed" + exit 1 + fi + done + bsize=2048 + for ffactor in 85 114 171; do + echo " bucketsize $bsize, fill factor $ffactor" + $PROG -o$TMP3 \ + -ibsize=$bsize,ffactor=$ffactor,nelem=25000,cachesize=65536\ + hash $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test20: type hash:\ +bsize=$bsize ffactor=$ffactor nelem=25000 cachesize=65536 failed" + exit 1 + fi + done + bsize=4096 + for ffactor in 171 228 341; do + echo " bucketsize $bsize, fill factor $ffactor" + $PROG -o$TMP3 \ + -ibsize=$bsize,ffactor=$ffactor,nelem=25000,cachesize=65536\ + hash $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test20: type hash:\ +bsize=$bsize ffactor=$ffactor nelem=25000 cachesize=65536 failed" + exit 1 + fi + done + bsize=8192 + for ffactor in 341 455 683; do + echo " bucketsize $bsize, fill factor $ffactor" + $PROG -o$TMP3 \ + -ibsize=$bsize,ffactor=$ffactor,nelem=25000,cachesize=65536\ + hash $TMP2 + if (cmp -s $TMP1 $TMP3) ; then : + else + echo "test20: type hash:\ +bsize=$bsize ffactor=$ffactor nelem=25000 cachesize=65536 failed" + exit 1 + fi + done +} + +# Test for a weird page split condition where an insertion into index +# 0 of a page that would cause the new item to be the only item on the +# left page results in index 0 of the right page being erroneously +# skipped; this only happens with one particular key+data length for +# each page size. +test40 () { + echo "Test 40: btree: page split on index 0" + e=: + for psize in 512 1024 2048 4096 8192; do + echo " page size $psize" + kdsizes=`awk 'BEGIN { + psize = '$psize'; hsize = int(psize/2); + for (kdsize = hsize-40; kdsize <= hsize; kdsize++) { + print kdsize; + } + }' /dev/null` + + # Use a series of keylen+datalen values in the right + # neighborhood to find the one that triggers the bug. + # We could compute the exact size that triggers the + # bug but this additional fuzz may be useful. + + # Insert keys in reverse order to maximize the chances + # for a split on index 0. + + for kdsize in $kdsizes; do + awk 'BEGIN { + kdsize = '$kdsize'; + for (i = 8; i-- > 0; ) { + s = sprintf("a%03d:%09d", i, kdsize); + for (j = 0; j < kdsize-20; j++) { + s = s "x"; + } + printf("p\nka%03d\nd%s\n", i, s); + } + print "o"; + }' /dev/null > $TMP2 + sed -n 's/^d//p' $TMP2 | sort > $TMP1 + $PROG -o $TMP3 -i psize=$psize btree $TMP2 + if (cmp -s $TMP1 $TMP3); then : + else + echo "test40: btree: page size $psize, \ +keylen+datalen=$kdsize failed" + e='exit 1' + fi + done + done + $e +} + +# Extremely tricky test attempting to replicate some unusual database +# corruption seen in the field: pieces of the database becoming +# inaccessible to random access, sequential access, or both. The +# hypothesis is that at least some of these are triggered by the bug +# in page splits on index 0 with a particular exact keylen+datalen. +# (See Test 40.) For psize=4096, this size is exactly 2024. + +# The order of operations here relies on very specific knowledge of +# the internals of the btree access method in order to place records +# at specific offsets in a page and to create certain keys on internal +# pages. The to-be-split page immediately prior to the bug-triggering +# split has the following properties: +# +# * is not the leftmost leaf page +# * key on the parent page is compares less than the key of the item +# on index 0 +# * triggering record's key also compares greater than the key on the +# parent page + +# Additionally, we prime the mpool LRU chain so that the head page on +# the chain has the following properties: +# +# * record at index 0 is located where it will not get overwritten by +# items written to the right-hand page during the split +# * key of the record at index 0 compares less than the key of the +# bug-triggering record + +# If the page-split bug exists, this test appears to create a database +# where some records are inaccessible to a search, but still remain in +# the file and are accessible by sequential traversal. At least one +# record gets duplicated out of sequence. + +test41 () { + echo "Test 41: btree: no unsearchables due to page split on index 0" + # list of individual retrievals in a variable for easy reuse + list=`(for i in a b c d; do + for j in 990 998 999; do + echo g ${i}${j} 1024 + done + done; + echo g y997 2014 + for i in y z; do + for j in 998 999; do + echo g ${i}${j} 1024 + done + done)` + # Exact number for trigger condition accounts for newlines + # retained by dbtest with -ofile but not without; we use + # -ofile, so count newlines. keylen=5,datalen=5+2014 for + # psize=4096 here. + (cat - <<EOF +p z999 1024 +p z998 1024 +p y999 1024 +p y990 1024 +p d999 1024 +p d990 1024 +p c999 1024 +p c990 1024 +p b999 1024 +p b990 1024 +p a999 1024 +p a990 1024 +p y998 1024 +r y990 +p d998 1024 +p d990 1024 +p c998 1024 +p c990 1024 +p b998 1024 +p b990 1024 +p a998 1024 +p a990 1024 +p y997 2014 +S +o +EOF + echo "$list") | + # awk script input: + # {p|g|r} key [datasize] + awk '/^[pgr]/{ + printf("%s\nk%s\n", $1, $2); + } + /^p/{ + s = $2; + for (i = 0; i < $3; i++) { + s = s "x"; + } + printf("d%s\n", s); + } + !/^[pgr]/{ + print $0; + }' > $TMP2 + (echo "$list"; echo "$list") | awk '{ + s = $2; + for (i = 0; i < $3; i++) { + s = s "x"; + } + print s; + }' > $TMP1 + $PROG -o $TMP3 -i psize=4096 btree $TMP2 + if (cmp -s $TMP1 $TMP3); then : + else + echo "test41: btree: failed" + exit 1 + fi +} + +# Test for recursive traversal successfully retrieving records that +# are inaccessible to normal sequential (sibling-link) traversal. +# This works by unlinking a few leaf pages but leaving their parent +# links intact. To verify that the unlink actually makes records +# inaccessible, the test first uses "o" to do a normal sequential +# traversal, followed by "O" to do a recursive traversal. +test50 () { + echo "Test 50: btree: recursive traversal" + fill="abcdefghijklmnopqrstuvwxyzy" + script='{ + for (i = 0; i < 20000; i++) { + printf("p\nkAA%05d\nd%05d%s\n", i, i, $0); + } + print "u"; + print "u"; + print "u"; + print "u"; + }' + (echo $fill | awk "$script"; echo o) > $TMP2 + echo $fill | + awk '{ + for (i = 0; i < 20000; i++) { + printf("%05d%s\n", i, $0); + } + }' > $TMP1 + $PROG -o $TMP3 -i psize=512 btree $TMP2 + if (cmp -s $TMP1 $TMP3); then + echo "test50: btree: unexpected success after unlinking pages" + exit 1 + fi + (echo $fill | awk "$script"; echo O) > $TMP2 + $PROG -o $TMP3 -i psize=512 btree $TMP2 + if (cmp -s $TMP1 $TMP3); then : + else + echo "test50: btree: failed" + exit 1 + fi +} + +test60 () { + echo "Test 60: btree: big key, small data, byteswap unaligned access" + # 488 = 512 - 20 (header) - 3 ("foo") - 1 (newline) + (echo foo; echo bar) | + awk '{ + s = $0 + for (i = 0; i < 488; i++) { + s = s "x"; + } + printf("p\nk%s\ndx\n", s); + }' > $TMP2 + for order in 1234 4321; do + $PROG -o $TMP3 -i psize=512,lorder=$order btree $TMP2 + done +} + +test61 () { + echo "Test 61: btree: small key, big data, byteswap unaligned access" + # 484 = 512 - 20 (header) - 7 ("foo1234") - 1 (newline) + (echo foo1234; echo bar1234) | + awk '{ + s = $0 + for (i = 0; i < 484; i++) { + s = s "x"; + } + printf("p\nk%s\nd%s\n", $0, s); + }' > $TMP2 + for order in 1234 4321; do + $PROG -o $TMP3 -i psize=512,lorder=$order btree $TMP2 + done +} + +test62 () { + echo "Test 62: btree: small key, big data, known byte order files" + (echo foo1234; echo bar1234) | + awk '{ + s = $0 + for (i = 0; i < 484; i++) { + s = s "x"; + } + printf("%s\n", s); + }' > $TMP1 + (echo g; echo kfoo1234; echo g; echo kbar1234) > $TMP2 + for f in t.le.db t.be.db; do + echo " $f" + $PROG -f $f -s -o $TMP3 btree $TMP2 + if (cmp -s $TMP1 $TMP3); then : + else + echo "test62: btree: failed" + exit 1 + fi + done +} + +test63 () { + echo "Test 63: btree: big key, medium data, bt_split unaligned access" + # 488 = 512 - 20 (header) - 3 ("foo") - 1 (newline) + # 223 = 232 - 8 (key pointer) + # 232 = bt_ovflsize = (512 - 20 (header)) / 2 (DEFMINKEYPAGE) + # - (2 (indx_t) + 12 (NBLEAFDBT(0,0))) + awk 'BEGIN { + s = ""; + for (i = 0; i < 488; i++) { + s = s "x"; + } + d = ""; + for (i = 0; i < 223; i++) { + d = d "x"; + } + for (i = 0; i < 128; i++) { + printf("p\nk%s%03d\nd%s\n", s, i, d); + } + }' /dev/null > $TMP2 + $PROG -o $TMP3 -i psize=512 btree $TMP2 +} + +main $* |
