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-rw-r--r--lib/libfigpar/string_m.c304
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diff --git a/lib/libfigpar/string_m.c b/lib/libfigpar/string_m.c
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-/*-
- * Copyright (c) 2001-2014 Devin Teske <dteske@FreeBSD.org>
- * All rights reserved.
- *
- * Redistribution and use in source and binary forms, with or without
- * modification, are permitted provided that the following conditions
- * are met:
- * 1. Redistributions of source code must retain the above copyright
- * notice, this list of conditions and the following disclaimer.
- * 2. Redistributions in binary form must reproduce the above copyright
- * notice, this list of conditions and the following disclaimer in the
- * documentation and/or other materials provided with the distribution.
- *
- * THIS SOFTWARE IS PROVIDED BY THE AUTHOR AND CONTRIBUTORS ``AS IS'' AND
- * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE
- * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE
- * ARE DISCLAIMED. IN NO EVENT SHALL THE AUTHOR OR CONTRIBUTORS BE LIABLE
- * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL
- * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS
- * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION)
- * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT
- * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY
- * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
- * SUCH DAMAGE.
- */
-
-#include <ctype.h>
-#include <errno.h>
-#include <stdint.h>
-#include <stdlib.h>
-#include <string.h>
-
-#include "string_m.h"
-
-/*
- * Counts the number of occurrences of one string that appear in the source
- * string. Return value is the total count.
- *
- * An example use would be if you need to know how large a block of memory
- * needs to be for a replaceall() series.
- */
-unsigned int
-strcount(const char *source, const char *find)
-{
- const char *p = source;
- size_t flen;
- unsigned int n = 0;
-
- /* Both parameters are required */
- if (source == NULL || find == NULL)
- return (0);
-
- /* Cache the length of find element */
- flen = strlen(find);
- if (strlen(source) == 0 || flen == 0)
- return (0);
-
- /* Loop until the end of the string */
- while (*p != '\0') {
- if (strncmp(p, find, flen) == 0) { /* found an instance */
- p += flen;
- n++;
- } else
- p++;
- }
-
- return (n);
-}
-
-/*
- * Replaces all occurrences of `find' in `source' with `replace'.
- *
- * You should not pass a string constant as the first parameter, it needs to be
- * a pointer to an allocated block of memory. The block of memory that source
- * points to should be large enough to hold the result. If the length of the
- * replacement string is greater than the length of the find string, the result
- * will be larger than the original source string. To allocate enough space for
- * the result, use the function strcount() declared above to determine the
- * number of occurrences and how much larger the block size needs to be.
- *
- * If source is not large enough, the application will crash. The return value
- * is the length (in bytes) of the result.
- *
- * When an error occurs, -1 is returned and the global variable errno is set
- * accordingly. Returns zero on success.
- */
-int
-replaceall(char *source, const char *find, const char *replace)
-{
- char *p;
- char *t;
- char *temp;
- size_t flen;
- size_t rlen;
- size_t slen;
- uint32_t n = 0;
-
- errno = 0; /* reset global error number */
-
- /* Check that we have non-null parameters */
- if (source == NULL)
- return (0);
- if (find == NULL)
- return (strlen(source));
-
- /* Cache the length of the strings */
- slen = strlen(source);
- flen = strlen(find);
- rlen = replace ? strlen(replace) : 0;
-
- /* Cases where no replacements need to be made */
- if (slen == 0 || flen == 0 || slen < flen)
- return (slen);
-
- /* If replace is longer than find, we'll need to create a temp copy */
- if (rlen > flen) {
- temp = malloc(slen + 1);
- if (temp == NULL) /* could not allocate memory */
- return (-1);
- memcpy(temp, source, slen + 1);
- } else
- temp = source;
-
- /* Reconstruct the string with the replacements */
- p = source; t = temp; /* position elements */
-
- while (*t != '\0') {
- if (strncmp(t, find, flen) == 0) {
- /* found an occurrence */
- for (n = 0; replace && replace[n]; n++)
- *p++ = replace[n];
- t += flen;
- } else
- *p++ = *t++; /* copy character and increment */
- }
-
- /* Terminate the string */
- *p = '\0';
-
- /* Free the temporary allocated memory */
- if (temp != source)
- free(temp);
-
- /* Return the length of the completed string */
- return (strlen(source));
-}
-
-/*
- * Expands escape sequences in a buffer pointed to by `source'. This function
- * steps through each character, and converts escape sequences such as "\n",
- * "\r", "\t" and others into their respective meanings.
- *
- * You should not pass a string constant or literal to this function or the
- * program will likely segmentation fault when it tries to modify the data.
- *
- * The string length will either shorten or stay the same depending on whether
- * any escape sequences were converted but the amount of memory allocated does
- * not change.
- *
- * Interpreted sequences are:
- *
- * \0NNN character with octal value NNN (0 to 3 digits)
- * \N character with octal value N (0 thru 7)
- * \a alert (BEL)
- * \b backslash
- * \f form feed
- * \n new line
- * \r carriage return
- * \t horizontal tab
- * \v vertical tab
- * \xNN byte with hexadecimal value NN (1 to 2 digits)
- *
- * All other sequences are unescaped (ie. '\"' and '\#').
- */
-void strexpand(char *source)
-{
- uint8_t c;
- char *chr;
- char *pos;
- char d[4];
-
- /* Initialize position elements */
- pos = chr = source;
-
- /* Loop until we hit the end of the string */
- while (*pos != '\0') {
- if (*chr != '\\') {
- *pos = *chr; /* copy character to current offset */
- pos++;
- chr++;
- continue;
- }
-
- /* Replace the backslash with the correct character */
- switch (*++chr) {
- case 'a': *pos = '\a'; break; /* bell/alert (BEL) */
- case 'b': *pos = '\b'; break; /* backspace */
- case 'f': *pos = '\f'; break; /* form feed */
- case 'n': *pos = '\n'; break; /* new line */
- case 'r': *pos = '\r'; break; /* carriage return */
- case 't': *pos = '\t'; break; /* horizontal tab */
- case 'v': *pos = '\v'; break; /* vertical tab */
- case 'x': /* hex value (1 to 2 digits)(\xNN) */
- d[2] = '\0'; /* pre-terminate the string */
-
- /* verify next two characters are hex */
- d[0] = isxdigit(*(chr+1)) ? *++chr : '\0';
- if (d[0] != '\0')
- d[1] = isxdigit(*(chr+1)) ? *++chr : '\0';
-
- /* convert the characters to decimal */
- c = (uint8_t)strtoul(d, 0, 16);
-
- /* assign the converted value */
- *pos = (c != 0 || d[0] == '0') ? c : *++chr;
- break;
- case '0': /* octal value (0 to 3 digits)(\0NNN) */
- d[3] = '\0'; /* pre-terminate the string */
-
- /* verify next three characters are octal */
- d[0] = (isdigit(*(chr+1)) && *(chr+1) < '8') ?
- *++chr : '\0';
- if (d[0] != '\0')
- d[1] = (isdigit(*(chr+1)) && *(chr+1) < '8') ?
- *++chr : '\0';
- if (d[1] != '\0')
- d[2] = (isdigit(*(chr+1)) && *(chr+1) < '8') ?
- *++chr : '\0';
-
- /* convert the characters to decimal */
- c = (uint8_t)strtoul(d, 0, 8);
-
- /* assign the converted value */
- *pos = c;
- break;
- default: /* single octal (\0..7) or unknown sequence */
- if (isdigit(*chr) && *chr < '8') {
- d[0] = *chr;
- d[1] = '\0';
- *pos = (uint8_t)strtoul(d, 0, 8);
- } else
- *pos = *chr;
- }
-
- /* Increment to next offset, possible next escape sequence */
- pos++;
- chr++;
- }
-}
-
-/*
- * Expand only the escaped newlines in a buffer pointed to by `source'. This
- * function steps through each character, and converts the "\n" sequence into
- * a literal newline and the "\\n" sequence into "\n".
- *
- * You should not pass a string constant or literal to this function or the
- * program will likely segmentation fault when it tries to modify the data.
- *
- * The string length will either shorten or stay the same depending on whether
- * any escaped newlines were converted but the amount of memory allocated does
- * not change.
- */
-void strexpandnl(char *source)
-{
- uint8_t backslash = 0;
- char *cp1;
- char *cp2;
-
- /* Replace '\n' with literal in dprompt */
- cp1 = cp2 = source;
- while (*cp2 != '\0') {
- *cp1 = *cp2;
- if (*cp2 == '\\')
- backslash++;
- else if (*cp2 != 'n')
- backslash = 0;
- else if (backslash > 0) {
- *(--cp1) = (backslash & 1) == 1 ? '\n' : 'n';
- backslash = 0;
- }
- cp1++;
- cp2++;
- }
- *cp1 = *cp2;
-}
-
-/*
- * Convert a string to lower case. You should not pass a string constant to
- * this function. Only pass pointers to allocated memory with null terminated
- * string data.
- */
-void
-strtolower(char *source)
-{
- char *p = source;
-
- if (source == NULL)
- return;
-
- while (*p != '\0') {
- *p = tolower(*p);
- p++; /* would have just used `*p++' but gcc 3.x warns */
- }
-}